Sanford and Son?

You be the judge!

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Kos-Kee-OOO-Sko Down!

The Kosciuszko Bridge (pronounced by some as “kos-kee-OOO-sko,” and by others as “kah-SHUS-ko”) connects Brooklyn with Queens. It is miserable. And now it is dead, having been replaced by a newer bridge to the side of it. The City imploded the bridge.

I passed through there last week. The traffic was so slow that I could take these photographs of the sections of the old hulk that was the Kosciuszko.

9ines

A Student (okay, my son Sammy, who is a 7th grade student), gave me this math puzzle:

“Use 6ix (sic) nines to equal 100, you can use +, -, x, ÷, ( ). [No exponents]. 9, 9, 9, 9, 9, 9. Good Luck, Sammy”

Welp, I was stumped and had to have him give me an answer.

This was his solution:

(9 x 9 + 9) + (9 ÷ 9 + 9)

which equals

90 + 10 = 100


I brought the problem to some colleagues of mine, and here are their answers:

Dennis wrote:

(999 – 99) ÷ 9

which equals

900 ÷ 9 = 100


Greg wrote:

(9 ÷ 9 + 9) x (9 ÷ 9 + 9)

which equals

10 x 10 = 100


I don’t remember who gave me this one:

99 + (9 ÷ 9) x (9 ÷ 9)

which equals

99 + 1  x  1

which equals

99 + 1 = 100


I finally came up with my own solution:

(99 ÷ 99) + 99

which equals

1 + 99 = 100

 

I happen to like my solution, since it uses the same numbers each time (99). However, Dennis’s is lovely, since it goes from three digits (999) to two digits (99) to one digit (9).

Which do you think is the most beautiful solution? The one that uses the most operations, or the one that uses the fewest?

November 2017
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